(ii) Have you made use of the right number of tall rates? thickness (1.03 ) enjoys step 3 tall figures regularity (1) has step 1 extreme shape Whenever multiplying or dividing, the amount of extreme numbers regarding the result is an identical due to the fact least amount of significant figures about terms and conditions made use of, therefore we is actually justified in using step one significant shape. Our address (ten30) keeps cuatro significant numbers! Just like the we’re simply https://datingranking.net/escort-directory/stamford/ rationalized in making use of step 1 tall profile, we are able to supply the respond to since the 1000 g, although best solution is to explore scientific notation and you can generate 1 ? 10 step 3 g
(iii) Can be your address plausible? Would a “rough” calculation: occurrence ≈ 1 grams mL -step one step 1 mL regarding milk products has actually quite a few regarding 1 g 1 L (one thousand mL) of milk possess quite a few from the a lot of ? step 1 = a thousand g Because this crude calculation is virtually the fresh cautiously calculated value to possess bulk we are reasonably positive that the answer is correct.
Question 5. From the twenty five°C and you may step one atm tension, diamond has a density regarding step 3.5 grams cm -step 3 . Calculate the volume within the cm step three away from 0.50 g from diamond at the 25°C and you will 1 atm stress.
step 3.5 grams cm -step three ? V (cm step three ) = V(cm 3 ) ? 0.fifty grams ? V (cm step 3 ) step three.5 g cm -step three ? V (cm 3 ) = 0.fifty g
[ step 3.5 grams cm -step three ? V (cm step 3 )] ? step 3.5 g cm -step three = 0.fifty g ? step three.5 g cm -3 V (cm step 3 ) = 0.50 ? step 3.5 (cm -3 ) = 0.fourteen cm 3
Perform an effective “rough” calculation: density ≈ 5 g cm -step three step 1 cm -step three of diamond has quite a few throughout the 5 g
(ii) Perhaps you have made use of the proper number of high data? occurrence (step 3.5) have 2 high figures regularity (0.50) provides dos high numbers When multiplying or splitting, what number of significant data from the result is a comparable just like the minimum quantity of extreme numbers regarding words put, so we was justified in making use of 2 significant numbers. All of our respond to (0.14) features 2 significant figures
(iii) Is your answer plausible? 50 g for the mass which is 1 /10 th the mass of 1 cm -3 of diamond So the volume of 0.50 g of diamond will 1 /10 th the volume that is V = 1 /10 ? 1 cm 3 = 0.1 cm 3 Since this “rough” answer is about the same as our carefully calculated answer we are reasonably confident that our answer is correct.
Concern six. From the twenty five°C and step one atm pressure, ethylene glycol keeps an occurrence of 1.eleven grams mL -step one . Estimate the volume in mL off 0.025 kilogram of ethylene glycol at twenty-five°C and you will step 1 automatic teller machine stress.
Convert mass in kg to help you bulk in the grams to help you remain consistent with equipment from occurrence (grams mL -step 1 ):
V (mL) ? step 1.eleven (grams mL -step 1 ) = V (mL) ? twenty five (g) ? V (mL) V (mL) ? 1.11 (g mL -1 ) = 25 (g)
The question provides 0
[V (mL) ? step 1.11 (grams mL -step one ) ] ? step one.eleven (grams mL -step 1 ) = twenty five (g) ? step 1.eleven ( grams mL -step 1 ) V (mL) = twenty-five ? step 1.11 (mL -1 ) = 23 mL
(ii) Have you made use of the proper number of significant data? mass (0.025) provides dos significant figures thickness (step 1.11) keeps 3 high numbers When multiplying otherwise separating, the number of extreme figures about outcome is an identical while the the very least amount of extreme rates regarding terms made use of, therefore we is rationalized in using dos extreme rates. Our answer (25) has actually dos tall data